Answer:
C.

Step-by-step explanation:
We have been given that Mike took out a $30,000 loan with a 7% annual interest rate. So the approximate amount, A(x), he has to pay on his loan at the end of each year as a function of x will be:



Using exponent property
we will get,



Therefore, the equation
represents the approximate amount, Mike has left to pay on his loan at the end of each year and option C is the correct choice.