Question

What is th product ? y2+3y+7 8y2+y+1

Answer 1

8y⁴+25y³+60y²+10y+7

Explanation:

Given two functions

y²+3y+7 and 8y²+y+1

To take the product of both functions means multiplying both functions together.

(y²+3y+7)(8y²+y+1)

Opening up the bracket we have:

= 8y⁴+y³+y²+24y³+3y²+3y+56y²+7y+7

Collecting the like terms

= 8y⁴+y³+24y³+y²+3y²+56y²+3y+7y+7

Adding up the functions with the same degree and simplifying the expression will give;

= 8y⁴+25y³+60y²+10y+7

This gives the product of both functions

Answer 2

Product is :(y²+3y+7)×(8y²+y+1) = 8y^4 + 25y^3 + 60y² + 10y + 7

Explanation:

We have given two equations:

y²+3y+7 and 8y²+y+1

Product of above two equations can be given as:

(y²+3y+7)×(8y²+y+1)

or (y².8y² + y².y + y².1) + (3y.8y² + 3y.y +3y.1)+(7.8y²+7.y+7.1)

or 8y^4 + y^3 +y² + 24y^3 + 3y² +3y + 56y² + 7y +7

or 8y^4 + 25y^3 + 60y² + 10y + 7 , this is the answer