Question

I need the solution

Answer 1

The only thing you can do here is to try to simplify, so I'll assume that's what you want to do.

`(b^2-a^2)/(2a^2+ab-3b^2)`

The numerator is a difference of squares, so it's easy to factorize:

`b^2-a^2=(b-a)(b+a)`

In the denominator, we factorize by grouping:

`2a^2+ab-3b^2=2a^2-2ab+3ab-3b^2=2a(a-b)+3b(a-b)=(2a+3b)(a-b)`

So we have

`(b^2-a^2)/(2a^2+ab-3b^2)=((b-a)(b+a))/((2a+3b)(a-b))=-(b+a)/(2a+3b)`