Answer: 0.0211 moles of air are present inside the bottle
Step-by-step explanation:
Volume of the bottle = 0.500 L
Standard Pressure exerted by the air = 1 atm
Temperature of bottle in which air is present = 15 °C= 288 K(0 °C = 273 K)
Assuming air inside the bottle is behaving ideally:
PV=nRT
![1 atm* 0.500 L=n* 0.0820 L atm/mol K* 288 K](https://img.qammunity.org/2020/formulas/chemistry/middle-school/txa0i64n12iwgksnzdsxo7bxs1uizzknv3.png)
![n=(1 atm* 0.500 L)/(0.0820 L atm/mol K* 288 K)](https://img.qammunity.org/2020/formulas/chemistry/middle-school/pa32v41qo4y848je4zngnezp37510012o5.png)
n = 0.0211 moles
0.0211 moles of air are present inside the bottle