Question

Triangle XYZ is translated 4 units up and 3 units left to yield ΔX'Y'Z'. What is the distance between any two corresponding points on ΔXYZ and ΔX'Y'Z′? A. units B. 5 units C. 7 units D. 25 units

Answer 1

The answer is B- 5 units

Answer 2

option B. 5 units.

Explanation:

If a Δ XYZ is translated 4 units up and 3 units left to yield X'Y'Z'.

If we consider one vertex X (x, y) of the triangle XYZ then after translation X will form new vertex as

x' (x-3, y-4)

Then we have to find the distance between x and x' after translation.

In the figure attached we have to find the distance a.

a² = 3² + 4² ( By Pythagoras Theorem)

a² = 9 + 16

a = √25 = 5 units

Therefore, answer will be option B. 5 units.