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Please, I NEED HELP. Anyone?

1. David would like to make a 280 lb. flour mixture that is 8% plain flour. He has bread flour that is 14% plain and cake flour that is 7% plain Let b represent the number of pounds of bread flour needed to make the new mixture and let c represent the number of pounds cake flour needed


(a) What is the system that models this situation?

(b) How many pounds of bread flour and cake flour will David need? Show your work and label your answers correctly


Hint: Remember to change the percentages into decimals.


Answer:

I would really appreiate the help.

User Legion
by
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1 Answer

1 vote

Answer:

(a) The system that models the situation:
b+c= 280 and
0.14b+0.07c= 22.4

(b) David needs 40 pounds of bread flour and 240 pounds of cake flour.

Explanation:

The amount of flour mixture is 280 lb. that is 8% plain flour.

So, the amount of plain flour in the mixture will be:
(280*0.08)lb.= 22.4 lb.

The number of pounds of bread flour and cake flour needed to make the new mixture are
b and
c respectively.

So, the first equation will be:
b+c= 280 ...................................(1)

The bread flour has 14% plain flour and the cake flour has 7% plain flour.

Thus, the amount of plain flour in bread flour
=0.14b lb. and the amount of plain flour in cake flour
= 0.07c lb.

So, the second equation will be:
0.14b+0.07c= 22.4 ................................(2)


From equation (1), we will get:
b= 280-c

Now substituting this
b= 280-c into equation (2) in place of
b........


0.14(280-c)+0.07c= 22.4\\ \\ 39.2-0.14c+0.07c=22.4\\ \\ -0.07c=22.4-39.2\\ \\ -0.07c=-16.8\\ \\ c=(-16.8)/(-0.07)=240

Plugging this
c=240 into equation (1), we will get.....


b+240=280\\ \\ b=280-240=40

So, David needs 40 pounds of bread flour and 240 pounds of cake flour.

User Ty Le
by
4.7k points