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PLEASE HELP

For j(x) = 4x − 2, find j of the quantity x plus h end quantity minus j of x all over h period


4 to the power of the quantity x minus 2 end quantity times the quantity 4 to the power of h end quantity all over h

4 to the power of the quantity x minus 2 end quantity times the quantity 4 to the power of h plus 1 end quantity all over h

4 to the power of the quantity x minus 2 end quantity times the quantity 4 to the power of h minus 1 end quantity all over h

the quantity x minus 2 end quantity times the quantity 4 to the power of h plus 1 end quantity all over h

PLEASE HELP For j(x) = 4x − 2, find j of the quantity x plus h end quantity minus-example-1
User Azim
by
3.1k points

2 Answers

20 votes
20 votes

Answer: It is C

Explanation:

Got it right

User Soham
by
3.0k points
10 votes
10 votes

Explanation:

The figure below shows a portion of the graph of the function
j\left(x\right) \ = \ 4^(x-2), hence the average rate of change (slope of the blue line) between the
x and
x+h is


\text{Average rate of change} \ = \ \displaystyle(\Delta y)/(\Delta x) \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle(f\left(x+h\right) \ - \ f\left(x\right))/(\left(x \ + \ h \right) \ - \ x) \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle(f\left(x + h\right) \ - \ f\left(x\right))/(h) \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle(4^(x+h-2) \ - \ 4^(x-2))/(h) \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle(4^(x-2+h) \ - \ 4^(x-2))/(h)


\\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle(\left(4^(x-2)\right)\left(4^(h)\right) \ - \ 4^(x-2))/(h) \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle(\left(4^(x-2)\right)\left(4^(h) \ - \ 1 \right))/(h)

PLEASE HELP For j(x) = 4x − 2, find j of the quantity x plus h end quantity minus-example-1
User Brad Crandell
by
3.5k points
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