Question

What is the probability of rolling an even number and then an odd number when rolling two number cubes?

Size of sample spaces = A)6 B)12 C)30 D)36

Number of desired outcomes = A)3 B)6 C)9 D)18

P(first is even and second is odd) = A)1/36 B)1/12 C)1/4 D)1/2

Answer 1

•Size of sample spaces= 36.

•Number of desired outcomes=9.

•P(first is even and second is odd)=1/4.

•To hard ???- 1st answer is D. 2nd answer is C. 3rd answer is C.

•Still too hard ;-;???- 1st answer is 36. 2nd answer is 9. 3rd answer is 1/4.

This is the best I could help , hope this will get you a ✅.♡

Explanation:

Just did it ^-^

Answer 2

1) Option D - 36

2) Option C - 9

3) Option C-
`(1)/(4)`

Explanation:

Given : Two dice are rolled and outcome is an even number and then an odd number.

To find :

1)Size of sample spaces

When two dice are rolled total no. of outcomes are
`6^2=36`

Therefore, Option D is correct - 36

2)Number of desired outcomes

Condition is first come even than odd on a dice

Favorable outcomes = (2,1),(4,1),(6,1),(2,3),(4,3),(6,3),(2,5),(4,5),(6,5)

Number of desired outcomes is 9

Therefore, Option C is correct- 9

3)P(first is even and second is odd)

Favorable outcomes = (2,1),(4,1),(6,1),(2,3),(4,3),(6,3),(2,5),(4,5),(6,5)

Total no. of outcomes = 36

`Probability = (Favorable outcome)/(Total outcomes)`

`Probability=(9)/(36)=(1)/(4)`

Therefore, Option C is correct -
`(1)/(4)`