Question

An athlete swims from the north end to the south end of a 50.0 m pool in 20.0 s and makes the return trip to the starting position in 22.0 s.

a. what is the average velocity for the first half of the swim?

b. what is the average velocity for the second half of the swim?

c. what is the average velocity for the roundtrip

Answer 1

a.2.5 m/s

b.2.27 m/s

c.2.38 m/s

Explanation:

We are given that an athlete swims from the north end to south end of a pool 50 m.

a.We have to find the average velocity for the first half of the swim.

We are given displacement=50 m

Time=20 s

Average velocity=
`(Displacement)/(time)=(50)/(20)=2.5 m/s`

Hence, the average velocity=2.5 m/s.

b.Displacement =50 m

Time=22 s

We have to find the average velocity for the second half of the swim.

Average velocity=
`(50)/(22)=(25)/(11)=2.27 m/s`

Hence,the average velocity=2.27 m/s

c.We have to find the average velocity for the roundtrip

Average velocity for the roundtrip=Mean of average velocity for the first half and average velocity for the second half

Average velocity for the roundtrip=
`(2.5+2.27)/(2)=2.38 m/s`

Hence, the average velocity for roundtrip=2.38 m /s

Answer 2

Answer: a) 2.5 meter per second

b) 2.27 meter per second

c) 2.38 meter per second

Explanation:

The formula to find average velocity is given by :-

`\text{Average velocity}=\frac{\text{total distance}}{\text{total time taken}}`

a) The average velocity for the first half of the swim=
`(50)/(20)=2.5\ ms^(-1)`

b) The average velocity for the second half of the swim=
`(50)/(22)=2.27\ ms^(-1)`

c) The average velocity for the roundtrip=
`(50+50)/(20+22)=(100)/(42)=2.38\ ms^(-1)`