Question

A sequence is defined by the function f(n)=f(n-1)+5. Where n represents the number of the term for n>1 and f(1)=-4. What are the first four terms of the sequence

Answer 1

Answer: The first four terms are -4, 1, 6 and 11.

Step-by-step explanation: The function which defines the given sequence is

f(n) = f(n-1) + 5, where 'n' is the number of terms for n>1 and the first term is

f(1) = -4.

So, second term = f(2) = f(1) + 5 = -4+5 = 1.

Third term = f(3) = f(2) + 5 = 1+5 = 6.

Fourth term = f(4) = f(3) + 5 = 6+5 = 11.

Thus, the first four terms of the sequence are -4, 1, 6 and 11.

Answer 2

The first four terms of the above sequence are 1, 6, 11, 16.

Explanation:

A sequence is defined by the function f(n)=f(n-1)+5.

Where n represents the number of the term for n>1

First Put n = 2

f(2)=f(2-1)+5.

= f (1) + 5

= -4 + 5

= 1

Second Put n = 3

f(3)=f(3-1)+5.

= f (2) + 5

= 1 + 5

= 6

Third Put n = 4

f(4)=f(4-1)+5.

= f (3) + 5

= 6+ 5

= 11

Second Put n = 5

f(5)=f(5-1)+5.

= f (4) + 5

= 11 + 5

= 16

Therefore the first four terms of the above sequence are 1, 6, 11, 16.