Answer:
In a right angle triangle ABC, at C = 90 degree as shown below
AC =BC and AB = 4 units
Let AC=BC= x units
Using Pythagoras theorem:
![AB^2 =AC^2+BC^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/tynf72rvfemm5c1st7vyegsk7gah142gx3.png)
then substitute the given values we get;
![4^2 = 2x^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/z26dbvg5zjbhtu75n1tnygvl62h2ue0bmr.png)
or
![16 = 2x^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/mtqi475pk73hagco7kfilucswp07esuj55.png)
Divide both sides by 2 we get;
![8 = x^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/l95miwr77fi81i3rwmm2tz2enqxyv3x78v.png)
Simplify:
![x= √(8) =2√(2) \text{units}](https://img.qammunity.org/2020/formulas/mathematics/high-school/si482uud8tnuyys7uw1123g2lpzr7zku4r.png)
Therefore, each of the legs would be
and
![BC = √(8) =2√(2) \text{units}](https://img.qammunity.org/2020/formulas/mathematics/high-school/fsg757h3usxt9tgrm6jsedzcnp32ya8cky.png)