Answer: The answer is 17.71%.
Step-by-step explanation: Given that Coram is preparing to shoot free throws at basketball practice.
The probability that Coram will make a free throw = 77% = 0.77.
So, the probability of Coram miss the throw = 1 - 0.77 = 0.23.
Therefore, the probability that he makes his first throw on the second shot
= probability of missing the throw in first shot × probability of making a throw
= 0.23 × 0.77
=0.1771
17.71%.
Thus, the required probability is 17.71%.