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The weight of a basketball is normally distributed with a mean of 17 oz and a standard deviation of 2 oz. Suppose 500 different basketballs are in a warehouse. About how many basketballs weigh more than 19 oz?

User Gal Talmor
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2 Answers

6 votes

Answer: 80 is the correct answer !

The weight of a basketball is normally distributed with a mean of 17 oz and a standard-example-1
User Mohamed Nuur
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2 votes

Answer:

79 balls.

Explanation:

We have been given that the weight of a basketball is normally distributed with a mean of 17 oz and a standard deviation of 2 oz.

Let us find the z-score for the weight 19 oz.


z=(x-\mu)/(\sigma)


z=(19-17)/(2)


z=(2)/(2)


z=1

Let us find P(z>1) using normal distribution table.


P(z>1)=1-0.84134


P(z>1)=0.15866

So the probability of a basketball having weight more than 19 oz is 0.15866. As there are 500 basketballs in the warehouse, so the total number of basketballs having a weight more than 19 oz will be:


\text{Total number of balls having weight more than 19 oz}=500* 0.15866


\text{Total number of balls having weight more than 19 oz}=79.33\approx 79

Therefore, 79 balls weigh more than 19 oz.

User Nateyolles
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