Answer:
4 and 2 are the required numbers which satisfies the given equations
Explanation:
Let the two numbers be x and y
According to the first condition
their is is 6
which is
x + y =6 ........................(i)
Now according to second condition
twice the first number i.e. 2x added to three time the second number i.e. 3y is 10
in form of equation it could be written as
2x + 3y = 10 ........................(ii)
Now from first equation we have
x + y =6
subtracting y from both sides
x = 6 - y .....................(iii)
Now putting this value of x in equation (ii)
equation (ii) is
2x + 3y = 10
Putting the value gives
2(6-y)+3y = 10
opening the brackets
12 - 2y + 3y = 10
12 - y = 10
subtracting 12 from both sides
12 - y -12 = 10 -12
it becomes
- y = -2
multiplying both sides by (-1)
it becomes
(-1)(-y) = (-2) * (-1)
y = 2
Now we got the value of y put it in equation iii which is
x = 6 -y
putting the value
x = 6 - 2
x = 4
So the two numbers are x = 4 and y = 2