Answer:
36,38 and 40 are the three consecutive even integers
Explanation:
As we Know that we have three consecutive even integers and even integers can be Obtained by adding or subtracting 2 from the given Number
Now According to the given condition we have three consecutive even integers
Let First even integer be x
Second even integer would be x + 2
Third even integer would be x + 2 + 2 = x + 4
Now According to the first condition
Sum of three integers = 114
so it would become
x + ( x + 2 ) + ( x + 4)=114 ................(i)
This would be the equation
Solving it
x + x + 2 + x + 4 = 114
3x + 6 =114
subtracting 6 from both sides
3x + 6 - 6 = 114 -6
3x = 108
Dividing both sides by 3
x = 108 /3
x = 36
Now second integer = x + 2 and third integer = x + 4
Putting the value of x
Second integer = 36 + 2 third integer = 36 +4
= 38 = 40
So three consecutive even integers are 36,38 and 40