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Which triangle congruence therom could be used to immediately show ABC=DBC

User KOB
by
5.2k points

2 Answers

3 votes

Answer:

Answers to the WACA Connections Academy Honors Geometry Semester A Exam are:

1.A

2.C

3.A

4.B

5.C

6.A

7.B

8.C

9.A

10.D

11.B

12.C

13.D

14.A

15.always

16.B

17.C

18.A

19.A

20.B

21.C

22.D

23.A

24.C

25.A

26.A

27.C

28.D

29.C

30.B

31.A

32.B

33.A

34.C

35.C

36.D

37.B

38.A

39.D

40.D

41.A

42.B

43.B

44.A

45.D

46.A

47.A

If these are wrong for anybody, let me know! Also sorry to those who don't take honors geometry



User Equitharn
by
4.6k points
1 vote

Answer:

ASA Congruence theorem

Explanation:

ASA Congruence theorem stats that if two angles and the side that joins the two angles are equal in two triangles, then the triangles are congruent.

In triangles, ΔABC and ΔDBC, it is clear that

BC = BC (common)

∠B = ∠B (common)

∠C = ∠C (common)

Hence, ΔABC ≅ ΔDBC by ASA congruence theorem.

User Damien Keitel
by
4.9k points