Question

Which of the following functions has the largest value when x = 4?

e(x) = x2 + 6x + 21
m(x) = 8x
v(x) = 31x

e(x)
v(x)
m(x)
All the functions are equal at x = 4.

Answer 1

m(x)

Explanation:

I just took this test and I believe that you meant m(x) = 8^2 and not m(x) = 8x

I got this correct on my quiz so I hope this helps.

Option 1:

Substitute x for 4

e(4) = (4)^2 + 6(4) + 21

e(4) = 16 + 24 + 21

e(4) = 61

Option 2:

v(4) = 31(4) = 124

Option 3:

m(4) = 8^(4)

m(4) = 4096

This shows that option 3, m(x) has the largest value when x = 4

Remember to always use ^ after the coefficient or before the exponent so there isn't confusion. :)

Answer 2

Answer:The function v(x) has the largest value when x = 4.
Solution:
x=4;
e(4) = 4^2 + 6×4 + 21=16+24+21=61
m(4) = 8×4=32
v(4) = 31×4=124
v(4)>e(4)>m(4)
Therefore,The function v(x) has the largest value when x = 4.