Question

A mass of 26.1 g of an element is known to contain 6.87 x 1023 atoms. What is the atomic mass of the element

Answer 1

Using Avogadro's law, we know the amount of moles in the sample is

`(6.87 * 10^(23))/(6.022 * 10^(23))=1.1408170043175 \text{ mol}`

Therefore, the atomic mass is:

`(26.1)/(1.1408170043175)=\boxed{22.9 \text{ g/mol (to 3 sf)}}`