Question

If DE=4x+10, EF =2x-1, and DF=9x-15, find DF

Answer 1

Explanation:

If DE = 4x+10,EF =2X -1, and DF= 9x - 15 find DF

(de + ef ) - df = 2e || 2e/2 = e || ed - e = d || ef - e = f || f + d = df

de + ef = 6x + 11 || (6x +11) - df = -3x -6 || 2e/2 = -3x/2 - 3 || (-3x/2 - 3) - de = x/2 + 7|| (- 3x/2 - 3) - ef = -x/2 - 1|| d + f = 6

Answer 2

`DF=201`

Explanation:

We have been given that segment
`DE=4x+10`, segment
`EF=2x-1` and
`DF=9x-15`

From the given information, we can set an equation as:

`DF=DE+EF`

`9x-15=4x+10+2x-1`

Combine like terms:

`9x-15=6x+9`

`9x-15+15=6x+9+15`

`9x=6x+24`

`9x-6x=6x-6x+24`

`3x=24`

`(3x)/(3)=(24)/(3)`

`x=24`

`DF=9x-15`

`DF=9(24)-15`

`DF=216-15`

`DF=201`

Therefore, DF equals 201 units.