Answer:
Accelerated motion is represented by a CURVED line on a nonlinear distance-time graph.
Step-by-step explanation:
For uniform acceleration we know that
![(dv)/(dt) = a](https://img.qammunity.org/2020/formulas/physics/middle-school/vjfit8z55j17oemykpbfm9avki6ri64n5r.png)
now integrating both sides we will have
![\int dv = \int adt](https://img.qammunity.org/2020/formulas/physics/middle-school/v4q164uz7yaxc3qb103iineoe38i4t59ww.png)
now after integration we will have
![v - v_o = at](https://img.qammunity.org/2020/formulas/physics/middle-school/dkk7v2870ebdobq92g3cupja1fwda4w56p.png)
now we have
![v = v_o + at](https://img.qammunity.org/2020/formulas/physics/middle-school/t21hfkrhxrdfn2bq5hwpcg869wo7afok5k.png)
again we know that
![(dx)/(dt) = v_o + at](https://img.qammunity.org/2020/formulas/physics/middle-school/27mvojrvc1tswheuos1hutzlrv0xxoavt6.png)
again by integration both sides
![x - x_0 = v_o t + (1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/middle-school/yqqwg2ky7354cb8079pa6ej5z63vt86d1r.png)
![x = x_0 + v_0t + (1)/(2)at^2](https://img.qammunity.org/2020/formulas/physics/middle-school/bmwakrjxka13lfukddvxkfh7j0t5wynipm.png)
now since this equation is a quadratic equation so here distance time graph must be a curved graph