Question

What is the result when 2x^3 - 9x^2 + 11x - 6 is divided by x-3

Answer 1

quotient = 2x² - 3x + 2 , remainder = 0

Explanation:

using the divisor as a factor in the numerator

2x²(x - 3) + 6x² - 9x² + 11x - 6

= 2x²(x - 3) - 3x(x - 3) - 9x + 11x - 6

= 2x²(x - 3) - 3x(x - 3) + 2(x - 3) + 6 - 6

= 2x²(x - 3) - 3x(x - 3) + 2(x - 3) + 0

`(2x^3-9x^2+11x-6)/(x-3)` = 2x² - 3x + 2