Question

A 70 kilogram mountaineer is standing on the summit of Mt. Everest. The distance between the mountaineer and the center of Earth is 6.39 × 10^6 meters. What is the magnitude of the force of gravity acting on the mountaineer? (The value of G is 6.673 × 10-11 newton meter2/kilogram2. The mass of Earth is 5.98 × 1024 kilograms.)

A. 90.5 newtons
B. 179 newtons
C. 648 newtons
D. 781 newtons

Answer 1

answer is 684 newtons on plato, got 100 on the test :)

Answer 2

Answer: 684 N

Step-by-step explanation:

The force of gravity between two objects having mass is given by:

`F=G(Mm)/(r^2)`

where, G is the gravitational constant,
`G= 6.673* 10^(-11) Nm^2/kg^2`, m is the mass of the man,
`m = 70 kg` and M is the mass of the Earth,
`M = 5.98 * 10^(24) kg` and r is the distance between two masses,
`r = 6.39 * 10^6 m`

`\Rightarrow F = 6.673* 10^(-11) Nm^2/kg^2* (5.98 * 10^(24) kg * 70 kg)/((6.39 * 10^6 m)^2) = 684 N.`

Thus, the magnitude of the force of gravity acting on the mountaineer is 684 N.