Question

A plane is flying at 32,500 feet. It needs to rise to 36,000 feet in two stages.

• In stage 1, it rises 5% of its initial altitude of 32,500 feet.
• In stage 2, it rises at a rate of 125 feet per minute.

How many minutes does it take for the plane to rise during stage 2?

Answer 1

Alright so if it rises 5% of initial height then we need to find that and add it to initial height

5% of 32500 is 1625
32500 + 1625 = 34125
now the height is 34125 and it needs to be at 36000
34125 + 125x = 36000
34125 + (125 * 15) = 36000,
it would take 15 minutes in stage 2

Answer 2

It will take 15 minutes in stage 2.

Step-by-step explanation

The plane was flying at 32,500 feet.

In stage 1, it rises 5℅ of its initial altitude of 32,500.

Let us calculate 5% of 32,500 to get,

`(5)/(100)* 32,500`

`=(5)/(1)* 325`

`=1625`

This means that, the plane rose, 1625 feet in the first stage.

Now, the current altitude of the plane is

`=32,500+1,625`

`=34,125` feet.

The plane needs to get to 36000 altitude.

The remaining altitude now is,

`=36,000-34,125`

`=1,875` feet.

This implies that, the plane needs to rise 1,875 feet in the second stage in order to get to the 36,000 feet altitude.

But we were given that, the plane rises 125 feet per minute in the second stage.

Therefore the number of minutes it will take to cover 1,875 altitude is

`=(1,875)/(125)`

`=15` minutes.