55.3k views
1 vote
Father is four times older than his son. In 14 years the father will be twice as old. What are their current ages?

User Dustinrwh
by
8.3k points

2 Answers

5 votes

Answer:

---

Explanation:

The son’s age is unknown, so call it: X

The father’s age, four times older, so that means: 4*X= 4X (I use * for multiply)

After 16 years, we add 16 to both ages:

Son: X+16

Father: 4X+16, now, after 16yrs father’s age 2x older than son:

father→ 4X+16 = 2(X+16) = 2X+32 (father twice older than the son age)

4X +16= 2X+32 (after opening the brackets)

4X-2X= 32 - 16 ——-> we moved 2X to left, turned minus -, we moved 16 to the right turned minus -

2X = 16

X = 16/2 = 8

Son’s age is 8 yrs old

Father(Sunil) age is 4x8= 32


After 16 yrs, Father’s age twice older:

8+16=24 (son)

32+16= 48 (Father,Sunil, twice older than son)

User StylusEater
by
8.8k points
7 votes

Answer:

The son is 7 years old

The father is 28 years old

Explanation:

f = fathers age

s = sons age

f = 4s

In 14 years ( so we add 14 to the age)

f+14 = 2(s+14)

We have 2 equations and 2 unknowns

Replace every f with 4s (from the first equation)

4s+14 =2(s+14)

Distribute the 2

4s+14 = 2s+28

Subtract 2s from each side

4s-2s+14 = 2s-2s+28

2s+14 = 28

Subtract 14 from each side

2s-14-14 = 28-14

2s = 14

Divide by 2

2s/2 =14/2

s =7

The son is 7 years old

Now lets calculate the fathers age

f =4s

f =4*7

f = 28

The father is 28 years old

User Tony Hopkinson
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories