Answer:
![40\pi \ m^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r0p89fn0rkmaj9ydop296kbme2k81gevwk.png)
Explanation:
we know that
The area of a circle is equal to
![A=\pi r^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2z11w6ajg8k9itft7shcdqinea4lmf008k.png)
In this problem we have
![r=10\ m](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rtndclf7sc4d23g2couz8jo6zjlxq4ycgn.png)
Substitute and find the area
![A=\pi (10)^(2)=100 \pi\ m^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hk57m4nxbnffna1epuj39b9f3htrjz8wcf.png)
Remember that
subtends the area of complete circle
so
by proportion
Find the area of the shaded regions
The central angle of the shaded regions is equal to
![2*72\°=144\°](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w7unta4y78lgp1em8j8hyxermtedgz5gzz.png)
![(100\pi )/(360) (m^(2))/(degrees) =(x )/(144) (m^(2))/(degrees) \\ \\x=144*100\pi /360\\ \\ x=40\pi \ m^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/57wg4idsrowbdd4h7oflqvwowng5hg91x1.png)