Question

Can anyone solve this? Thanks

Answer 1

Expression will be 5
`N^(2)` =
`3^(2)`×
`5^(5)`×
`x^(6)`

Explanation:

As given in the question a number N is expressed as a product of its prime factors in index form is N = 3×
`5^(2)`×
`x^(3)`

Now we have to express 5
`N^(2)` as a product of prime factors in index form.

For this we write the equation N×N= (3×
`5^(2)`×
`x^(3)`)×((3×
`5^(2)`×
`x^(3)`)

`N^(2)`=3×3×
`5^(2)`×
`5^(2)`×
`x^(3)`×
`x^(3)`

`xN{2}` =
`3^(2)`×
`5^(4)`×
`x^(6)`

Then 5
`N^(2)` = 5×
`3^(2)`×
`5^(4)`×
`x^(6)`

5
`N^(2)` =
`3^(2)`×
`5^(5)`×
`x^(6)`