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In the circle m∠ACD=2x+14 and m∠ABD=3x+8
what is the value of x

In the circle m∠ACD=2x+14 and m∠ABD=3x+8 what is the value of x-example-1
User Rappongy
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1 Answer

2 votes

Answer:

The value of x = 6

Explanation:

The angle subtended on same arc are equal in measure.Here <ACD and <ABD are on the same arc. therefore these two angle are equal.

it is given that, m∠ACD=2x+14 and m∠ABD=3x+8

From the figure we get,

m∠ACD = m∠ABD

Therefore we can write,

2x+14 = 3x+8

3x - 2x = 14 - 8

x = 6

Therefor the value of x = 6

User Nico Schuck
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