Question

Please help me with thus

Answer 1

`- 2 \: = \: (2x \: + \: 1)/(6x \: + \: 3)`
Multiplying and Dividing R.H.S. by 3, we get,

`- 2 \: = \: (1)/(3) \: * \: (6x \: + \: 3)/(6x \: + \: 3)`
or,

`- 2 \: = \: (1)/(3)`
Which is not possible, so, no such equation can exist.
Hence, the answer is (C) as the denominator becomes 0, which doesn't make sense, as it is an Indeterminate form.

Answer 2

The answer for this question would be C. This statement supports his answer because a solution is not possible when the denominator of a fraction is equal to zero, making it undefined. This is shown when -1/2 is plugged into 6x+3, the denominator of the equation, and it results in the answer 0.