Answer:
The correct answer option is A) 5.
Step-by-step explanation:
We are given the following expression and we are to factorize it:
![5x^3-135](https://img.qammunity.org/2020/formulas/mathematics/high-school/lvrz6vhvd473lz54y4h4o1s8d2bdkaeb6n.png)
If we take the common term out of this, then we are left with:
![5(x^3-27)](https://img.qammunity.org/2020/formulas/mathematics/high-school/obsck8h5cx0gfyy12ee8m06oa38fuu3dkz.png)
Now the term
can also be written in the form of
as:
![x^3-3^3](https://img.qammunity.org/2020/formulas/mathematics/high-school/3sou1ixcz0xt7nq3qq88gdvr2z1gao6kv2.png)
Next, we will factorize it applying the difference of cubes formula
to get:
![x^3-3^2= \left(x-3\right)\left(x^2+3x+3^2\right)](https://img.qammunity.org/2020/formulas/mathematics/high-school/zb8zec6j3cs7fc5zuh08j8gi4cc2he9i4c.png)
![=\left(x-3\right)\left(x^2+3x+3^2\right)](https://img.qammunity.org/2020/formulas/mathematics/high-school/8a67m4vn2fkdwzef0uuie02fejbdnqqq9w.png)
![=\left(x-3\right)\left(x^2+3x+9\right)](https://img.qammunity.org/2020/formulas/mathematics/high-school/qm0ak3vygzez972wnopwjr8vq1wz6f62rg.png)
Adding the common term back to it to get:
![5\left(x-3\right)\left(x^2+3x+9\right)](https://img.qammunity.org/2020/formulas/mathematics/high-school/rf6ay9v248vjzfsvi2onu3i8misnf8so0t.png)
Therefore, from the given answer options we can see that the option A) 5 is the factor of the given expression 5x^3 - 135.