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Solve 2x2 + 3x = −8.

A) the quantity of negative 3 plus or minus 11 i all over 4
B) the quantity of negative 3 plus or minus i square root 55 all over 4
C) negative 3 plus or minus i square root 23
D) 3 plus or minus i square root 11

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Answer:

Final answer iis choice B)
x=(-3\pm i√(55))/(4)

Explanation:


2x^2 + 3x =-8


2x^2 + 3x +8 = 0

Compare with quadratic equation
ax^2 + bx +c = 0, we get:

a=2, b=3, c=8

Now plug these values into quadratic formula:


x=(-3\pm √(\left(3\right)^2-4\left(2\right)\left(8\right)))/(2\left(2\right))


x=(-3\pm √(9-64))/(4)


x=(-3\pm √(-55))/(4)


x=(-3\pm i√(55))/(4)

Hence final answer iis choice B)
x=(-3\pm i√(55))/(4)

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