Answer: The vertex is (-3, 2)
The equation y = -4(x + 3)^2 + 2 can be written as y = -4(x - (-3))^2 + 2
I rewrote x+3 as x - (-3)
Compare y = -4(x - (-3))^2 + 2 with the general template y = a(x-h)^2 + k
Note how
a = -4
h = -3
k = 2
So the vertex is (h,k) = (-3, 2)