Question

Two different linear functions are shown below with two points given from each function. Use slope-intercept form or point-slope form to find the equation of each.

Linear Function A

Points: (–5, –2), (–5, 7)

Linear Function B

Points: (7, –5), (–2, –5)

Answer 1

This is late but the correct answers are

Function A has no slope

The equation of line A is x=-5

Function B has a slope of 0

The equation of line B is y=-5

The other explanation didn't make much sense to me so if anyone needs the answers they're here now lollllllllllllll

Answer 2

The equation of function A is
`x=-5` and the equation of function B is
`y=-5`.

Explanation:

The point slope form of a linear function is

`y-y_1=m(x-x_1)`

Where m is slope.

`m=(y_2-y_1)/(x_2-x_1)`

It is given that the function A passing through the points (–5, –2) and (–5, 7).

The equation of function A is

`y-(-2)=(7-(-2))/(-5-(-5))(x-(-5))`

`y+2=(7+2)/(-5+5)(x+5)`

`y+2=(9)/(0)(x+5)`

`(y+2)0=9(x+5)`

`0=9(x+5)`

`0=x+5`

`x=-5`

It is given that the function B passing through the points (7, –5) and (–2, –5).

The equation of function B is

`y-(-5)=(-5-(-5))/(-2-7)(x-7)`

`y+5=(0)/(-9)(x-7)`

`y+5=0`

`y=-5`

Therefore equation of function A is
`x=-5` and the equation of function B is
`y=-5`.