Answer:∠JML ≅ ∠QJM
Alternate Interior Angles Theorem
Explanation:
Here, Given: JKML is a parallelogram,
That is, JK ║ ML and JM ║ KL
Prove: ∠ MLK ≅ ∠ KJM and ∠ JML ≅ ∠ LKJ
Extend segment JM beyond point and draw point P (Construction)
∠ MLK ≅ ∠ PML ( Alternate Interior Angles Theorem)
∠ PML ≅ ∠KJM ( Corresponding Angles Theorem )
⇒ ∠ MLK ≅ ∠ KJM ( By transitive property of equality )
Extend segment JK beyond point J and draw point Q, by Construction.
∠JML ≅ ∠QJM ( Alternate Interior Angles Theorem)
∠ QJM ≅ ∠ LKJ ( Corresponding Angles Theorem )
⇒ ∠JML ≅ ∠ LKJ ( By transitive property of equality )
Thus, the opposite angles of parallelogram JKLM are congruent.