Answer
The correct answer is B
Explanation
The y-component of the vector is opposite to the given angle which is
. See diagram.
The hypotenuse, which is the magnitude of the vector is
units.
The y-component of the vector can be found using the sine ratio.
Recall that the mnemonics for the sine ratio is SOH which means
![\sin\theta=(Opposite)/(Hypotenuse)](https://img.qammunity.org/2020/formulas/physics/high-school/6uaps2whbu5f8xjti2qn6by7m6kzbw2jnn.png)
This implies that,
![\sin81\degree=(y)/(17)](https://img.qammunity.org/2020/formulas/physics/high-school/qd5dmr8ulqoapr7jn3v8m0sl3r4iy8aiuy.png)
We multiply both sides by 17 to get,
![y=17\sin81\degree](https://img.qammunity.org/2020/formulas/physics/high-school/dde2kreygb8j3k8pji7kqzxhbiuxcwoe3m.png)
This gives us
![y=17(0.9877)](https://img.qammunity.org/2020/formulas/physics/high-school/4cce10gxwfpmic9lkq8dh4l36y64b7ljb2.png)
We evaluate to get,
![y=16.79](https://img.qammunity.org/2020/formulas/physics/high-school/9mod2acdvdfom0n0kymadhd7xqztfsl9sh.png)
The y-component of the vector is
to the nearest tenth.