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5 votes
5 votes
A 6-sided die is loaded in such a way where odd outcomes occur 2/9 of the time, and even outcomes happen the other

1/9 of the time. What is this die's expected value?
A. 3.25
B. 4
C. 3.5
D. 3.33

User Leonardo Alves
by
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1 Answer

12 votes
12 votes

Answer:

3.33, or 3 1/3

Explanation:

Expected value:


(9 * (2)/(9) ) + (12 * (1)/(9) ) = 2 + (4)/(3) = 2 + 1 (1)/(3) = 3 (1)/(3)

User Larhonda
by
2.7k points