Question

How do you solve:

`x^(4) -8x^(3) + 24x^(2) -32x+16=0`

Answer 1

x = 2

Explanation:

Solve for x over the real numbers:

x^4 - 8 x^3 + 24 x^2 - 32 x + 16 = 0

Write the left hand side as a power:

(x - 2)^4 = 0

Take the 4^th root of both sides:

x - 2 = 0

Add 2 to both sides:

Answer: x = 2