Question

HELPPPPP PLEASE ASAP!!!!!!!! 50 POINTS!!!!!!!!!!!!!!

1.) Find the value of the expression


5x2–(3xy–7x2)+(5xy–12x2) when x=−0.25 and y=4

5x2–(3xy–7x2)+(5xy–12x2) When x=−5 and y=0.1


2.) What binomial do you have to add to the polynomial x2+y2–2xy+1 to get a polynomial:

not containing the variable x

2.a) What binomial do you have to add to the polynomial x2+y2–2xy+1 to get a polynomial:

not containing the variable y?

Answer 1

wsxcvbjkoiuytre

Explanation:

Answer 2

• 1a. -2
• 1b. -1

• 2a. 2xy-x²
• 2b. 2xy-y²

Explanation:

1. The expression simplifies to ...

... = 5x² -3xy +7x² +5xy -12x²

... = (5+7-12)x² +(-3+5)xy

... = 2xy

1a. for (x, y) = (-0.25, 4), -2xy = -2

1b. for (x, y) = (-5, 0.1), -2xy = -1

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2. To eliminate the terms you don't want, add their opposite.

2a. The terms you don't want are x²-2xy. To get rid of them, add the opposite of this sum: 2xy -x².

2b. The terms you don't want are y²-2xy. Add their opposite: 2xy-y².

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Comment on point value

Last time I checked, 5 (or 8) and 50 were very different things.