Question

Given the quadrilateral below is a rhombus, solve for the length of the side of the rhombus.

Answer 1

The diagonals of the rhombus meet perpendicularly, so you have four right triangles. Because of this you can use the Pythagorean theorem with 8 and 12 to find the side.

Theorem: a^2 + b^2 = c^2

8^2 + 12^2 = c^2
64+144 = c^2
c^2 = 208
c = sqrt208

Answer 2

7.21

Explanation:

There is a formula to find the area of a side of a rhombus given 2 diagonals.

It is:
`\frac{\sqrt{p^(2)+q^(2) } }{2}`

64 + 144 = 208

`√(208)` = 14.42

14.42 / 2 =

7.21