Solution:
A number is said to be irrational , if the decimal expansion of a number is non terminating non repeating.
For example , 2.01001000100001......., √3,∛5,....
Now coming to Options
(A) 4 + 2.5
4 as well as 2.5 is rational . So sum of two rational is a rational.
(B) 3 ×
![(1)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o08xg954t1gbzo9avralvfomcybk63rm02.png)
Since 3 is rational , but
is irrational. So product of rational and irrational should be irrational.
Because
= 0.333333.......(non terminating non repeating)
But numerator which is 3 and denominator which is 3 cancels out and result is 1 which is rational number.
(C) 2 × (real number=a )raised to power of 7
=
![2 (a)^7](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xptf8wji2687tce3e1a1ml961aw2yl9cus.png)
=
has denominator of the form other than
, then it is irrational number.
So,
is rational or irrational depends on the value of a.
(D) 1.25 + 4.25
Both 1.25 as well as 4.25 are rational. So their sum is rational.
So, option (C)
may be irrational , it totally depends on the value of a.