Answer:
For A: The volume of solution is 0.02 L
For B: The volume of concentrated
solution is 5 mL
For C: The molarity of diluted NaOH is 0.4 M
Step-by-step explanation:
To calculate the volume for given molarity, we use the equation:

Molarity of lead (II) nitrate solution = 2.50 M
Moles of lead ions = 0.0500 mol
Putting values in above equation, we get:

Hence, the volume of solution is 0.02 L
To calculate the molarity of the diluted solution, we use the equation:
......(1)
where,
are the molarity and volume of the concentrated solution
are the molarity and volume of diluted solution
We are given:

Putting values in equation 1, we get:

Hence, the volume of concentrated
solution is 5 mL
We are given:

Putting values in equation 1, we get:

Hence, the molarity of diluted NaOH is 0.4 M