Answer:
No extraneous solution
Explanation:
We have the logarithmic equation given by,
![\log_(2)[\log_(2)(√(4x))]=1](https://img.qammunity.org/2020/formulas/mathematics/high-school/nlm47uk55ymcdeaa98fcbmi51nqfxst10z.png)
i.e.
![\log_(2)(√(4x))=2^(1)](https://img.qammunity.org/2020/formulas/mathematics/high-school/uikmjci1sd3v9kbjsyj4zygkmaku2eazeb.png)
i.e.
![√(4x)=2^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/355s18rks4b09lul59iggts6opb0illek5.png)
i.e.
![√(4x)=4](https://img.qammunity.org/2020/formulas/mathematics/high-school/loayvnofq8gmu7bc3b4n6mn2amjn1c9z7q.png)
i.e.
![4x=4^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/dz6lub268j6fzcgsprbgtjyirtbeynw7hb.png)
i.e.
![4x=16](https://img.qammunity.org/2020/formulas/mathematics/high-school/9ida9tg98qdpihy4hpk2rt0lcm2npk4ehs.png)
i.e.
![x=4](https://img.qammunity.org/2020/formulas/mathematics/high-school/hxnxycp7ditjozikbfiiya3nb2g21vrzay.png)
So, the solution of the given equation is x=4.
Now, as we domain of square root function is x > 0 and also, the domain of logarithmic function is
.
Therefore, the domain of the given function is x > 0.
We know that the extraneous solution is the solution which does not belong to the domain.
But as x=4 belongs to the domain x > 0.
Thus, x = 4 is not an extraneous solution.
Hence, this equation does not have any extraneous solution.