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A bag contains 2 red marbles, 2 green marbles, and 4 blue marbles. If we choose a marble, then another marble without putting the first one back in the bag, what is the probability that the first marble will be red and the second will be green?

User Manis
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2 Answers

3 votes

Answer:

1/14

Explanation:

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User Fatima Zohra
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2 votes

A bag contains 2+2+4=8 marbles in total.

We have to find the probability of the following events:

1. We have to choose a red marble from the bag that contains 8 marbles in total, 2 of them are red

2. We have to choose a green marble from the bag that contains 7 marbles in total, 2 of them are green.

The probability of the first event to happens is:


P_1=(2)/(8)=(1)/(4)

The probability of the second event to happen is:


P_2=(2)/(7)

The probability of both events to happen is:


P=P_1\cdot P_2=(1)/(4)\cdot (2)/(7)=(1)/(14)=0.0714

User Andrew Neilson
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5.9k points