Question

when joe bowls he can get a strike 60% of the time, what is the probability jow will get at least 3 strikes out of 4 tries?

Answer 1

34.56%

Explanation:

This is a binomial probability that can easily be solved using the formula:

`p(x)=(n!)/(x!(n-x)!)*p^xq^(n-x)`

Where

• n is the total number of trials (here it is 4)
• x is the number of "success" ( here it is 3)
• p is the success rate (given as 60%=0.6)
• q is the not success rate ( it is 1 - p, so 0.4)

Substituting these values into the formula gives us our answer:

`p(x)=(n!)/(x!(n-x)!)*p^xq^(n-x)\\p(x)=(4!)/(3!(4-3)!)*(0.6)^(3)(0.4)^(4-3)\\p(x)=(4!)/(3!1!)*(0.6)^(3)(0.4)^(1)\\p(x)=0.3456`

In percentage, the probability is 34.56%