Question

A linear function contains these points: (0,-1) & (3,8)

What is the slope and y-intercept of this function?

Answer 1

SOLVING

`\Large\maltese\underline{\textsf{A. What is Asked}}`

If a linear function contains these points: (0,-1) and (3,8), what is its slope and y-int.?

`\Large\maltese\underline{\textsf{B. This problem has been solved!}}`

Formula utilised, here
`\bf{(y2-y1)/(x2-x1)}`.

Put in the values,

`\bf{(8-(-1))/(3-0)}` | subtract on top and bottom

`\bf{(9)/(3)}` | divide on top and bottom

`\bf{3}`

The y-intercept is the second co-ordinate of the point (0,-1)

`\bf{Which\;is\;-1}`.

`\cline{1-2}`

`\bf{Result:}`

`\bf{\begin{cases} \bf{Slope=3} \\ \bf{Y-int. -1} \end{cases}`

`\LARGE\boxed{\bf{aesthetic\\ot1 \theta l}}`

Answer 2

slope: 3

y-intercept: (0, -1)

Find slope:

`\sf slope : (y_2 - y_1)/(x_2- x_1) = (\triangle y)/(\triangle x) \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points`

Here given points are: (0, -1), (3, 8)

`\rightarrow \sf slope : (8-(-1))/(3-0) = (9)/(3) = 3`

When finding y-intercept, the value of x is 0. Here given y is -1 when x is 0.

y-intercept: -1 or (0, -1)