114,030 views
28 votes
28 votes
Find the point Q along the directed line segement from point R (-3, 3) to point S(6, -3) that divides the segment in the ratio 2:1.

A. (3, 0)
B. (6, -4)
C. (0, 1)
D. (3, -1)

User Peter Kneale
by
2.9k points

2 Answers

24 votes
24 votes

Answer:

D

Explanation:

using the section formula

(x₁, y₁ ) and (x₂, y₂ ) divided in the ratio m : n , then

point = (
(mx_(2)+nx_(1) )/(m+n) ,
(my_(2)+ny_(1) )/(m+n) )

thus for R (- 3, 3 ) and S (6, - 3 ) in the ratio 2 : 1

Q = (
(2(6)+1(-3))/(2+1) ,
(2(-3)+1(3))/(2+1) )

= (
(12-3)/(3) ,
(-6+3)/(3) )

= (
(9)/(3) ,
(-3)/(3) )

= (3, - 1 )

User Makstaks
by
3.2k points
19 votes
19 votes

Answer: (3,-1)

Explanation:

distance between R & S x values: 9

distance between R & S y values: -6

multiply each by 2/3 (the proportion)

9/1 x 2/3 = 6; -6/1 x 2/3= -4

add the answers to R x & y values:

-3 + 6= 3; 3 - 4= -1

User ZerosAndOnes
by
3.4k points