Question

Please help!!


36y=y(5y+9)

Answer 1

36y=5y^2+9y

5y^2-27y=0

y(5y-27)=0

y=0 or 5y=27 ⇒y=
`(27)/(5)`

From step 3 to step 4, you must use the 0 property rule that says that is the product of 2 (may vary) roots equals 0, then the roots are when each factor equals 0.

Answer 2

y=0 and y = 27/5

Explanation:

36y=y(5y+9)

Distribute

36y = 5y^2 +9y

Subtract 9y from each side

36y-9y = 5y^2 +9y-9y

27 y = 5y^2

Subtract 27 y from each side

27 y-27y = 5y^2-27y

0 = 5y^2-27y

Factor out y

0 =y( 5y-27)

Using the zero product property

y= 0 and 5y-27= 0

Add 27 to each side

5y -27+27 = 27

5y = 27

Divide by 5

5y=/5 = 27/5

y =27/5