Question

and electric motor lifts an elevator a vertical distance of 18.0m in a time of 30.0s by exerting an upward force of 6.0x10^3 N . what power does the electric motor produce?

Answer 1

`\fbox {3.6kW}`

Step-by-step explanation:

Formula used :

`\boxed {P = F * v} \leftarrow \rightarrow \boxed {P = (F * S)/(t)}`

Given :

⇒ F = 6 × 10³ N

⇒ S = 18 m

⇒ t = 30 s

Solving :

⇒ P = 6 × 10³ × 18 / 30

⇒ P = 2 × 100 × 18

⇒ P = 3600 W

⇒ P = 3.6kW