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The table has a set of equations that have arithmetic operations between rational and irrational numbers. Complete the table to find the sum. Then indicate whether the sum is rational or irrational.

The table has a set of equations that have arithmetic operations between rational-example-1
User Shabaz
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2 Answers

0 votes

Answer:

1. rational

2.irrational

3.irrational

4.rational

5.rational

6.irrational

Explanation:

User Van Peer
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6 votes

Answer:


Explanation:

According to given equation

A =
√(16) +(-(21)/(5)) ;
√(16) can be simplified to 4.

Sum :
√(16) +(-(21)/(5)) =
(20-21)/(5) =-(1)/(5)

4 is a rational number and
(-(21)/(5)) is also a rational number.

Sum of two rational number is always a rational number.

Therefore,
√(16) +(-(21)/(5)) is a rational number.

B = π+24 ; π is an irrational and 24 is a rational number.

Sum of an irrational and a rational is always a rational number.

Therefore, π+24 is an irrational number.

Sum = π+24

C =
√(4) +5 ;
√(4) can be simplified to 2.

2 is a rational number and 5 is also a rational number.

Sum = 2+5=7

Sum of two rational number is always a rational number.

Therefore,
√(4) +5 is a rational number.

D =
√(8)+π ; π is an irrational and
√(8) is also an irrational number.

Sum =
2√(2)

Sum of two irrational number is always an irrational number.

Therefore,
√(8)+π is an irrational number.

E=
√(36) +\sqrt[3]{27};
√(36) can be simplified to 6 and
\sqrt[3]{27} can be simplified to 3.

6 is a rational number and 3 is also a rational number.

Sum = 6+3=9.

Sum of two rational number is always a rational number.

Therefore,
√(36) +\sqrt[3]{27} is a rational number.

F =
(3)/(4) +√(27) ; \frac{3}{4} is a rational number and \sqrt{27} an irrational number.

Sum =
(3)/(4) +3√(3)=(3+12√(3))/(4)

Sum of an irrational and a rational is always a rational number.

Therefore,
(3)/(4) +√(27) is an irrational number.

User Nico Burns
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