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Consider this reaction: H2S + HNO3 S + NO + H2O Reduction half-reaction: N+5 + 3e- N+2 Oxidation half-reaction: S-2 S + 2e- After balancing the chemical equation, what are the coefficients for these compounds?

User Admax
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2 Answers

5 votes

Answer: 1. 3

2. 2

Step-by-step explanation:

User Oleksii Balenko
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3 votes

Answer:

Coefficient of
H_2S = 3

Coefficient of
HNO_3 = 2

Coefficient of
NO = 2

Coefficient of
H_2O = 4

Coefficient of
S = 3

Step-by-step explanation:

Overall reaction


H_2S + HNO_3\rightarrow S + NO + H_2O

Reduction half-reaction:


N^(+5) + 3e^-\rightarrow N^(+2)...(1)

Oxidation half-reaction:


S^[-2}\rightarrow S + 2e^-...(2)

2×(1) + 3×(2)


2N^(+5) + 6e^-+3S^[-2}\rightarrow 2N^(+2)+3S + 6e^-


2N^(+5) +3S^[-2}\rightarrow 2N^(+2)+3S


3H_2S + 2HNO_3\rightarrow 3S + 2NO + 4H_2O

Coefficient of
H_2S = 3

Coefficient of
HNO_3 = 2

Coefficient of
NO = 2

Coefficient of
H_2O = 4

Coefficient of
S = 3

User Cassiana
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