Answer:
The cost of 1 adult ticket is $9.5
The cost of 1 child ticket is $6.5
Explanation:
Given :
The price of 4 adult tickets and 6 child tickets is $77.
The price of 6 adult tickets and 4 child tickets is $83.
To Find : he ticket price for one adult and for one child.
Solution :
Let the cost of one ticket of adult be $x
Cost of 4 adult tickets = $4 x
Cost of 6 adult tickets = $6 x
Let the cost of one ticket of child be $y
Cost of 6 child tickets = $6 x
Cost of 4 child tickets = $4 x
Now , we are given that the price of 4 adult tickets and 6 child tickets is $77.
⇒
---(a)
Also we are given that price of 6 adult tickets and 4 child tickets is $83.
⇒
---(b)
Now solve equation (a) and (b) by substitution method
Substituting value of x from equation (a) in equation (b)
![6((77-6 y)/(4)) +4 y =83](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9sfjzbr3anvl3xq99myzyc3xep54viuem5.png)
![(462-36 y)/(4) +4 y =83](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ndqr4uzywwonyk6kq6knmz7zxcsitkyznq.png)
![115.5-9 y +4 y =83](https://img.qammunity.org/2020/formulas/mathematics/middle-school/slwb7w4mzwaexizacxr0peeime4w7gfb2s.png)
![115.5-5y =83](https://img.qammunity.org/2020/formulas/mathematics/middle-school/eieyxzflxgjjlg7hgjc3pzm9anz475wjui.png)
![115.5-83 =5y](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hfn1kfj2y8n5lwpq14ny5tno1yehg7gjso.png)
![32.5 =5y](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9l4rb21ji1suktwjvgnlufriv4icktyyie.png)
![(32.5)/(5) =y](https://img.qammunity.org/2020/formulas/mathematics/middle-school/to2xexv9ja1tnescwq6wpnlydrfp3jxytw.png)
![6.5=y](https://img.qammunity.org/2020/formulas/mathematics/middle-school/urpcl8cd6u0nkan40n4tvd5hcmllsl5yl6.png)
Thus, The cost of 1 child ticket is $6.5
To calculate x put y in equation (a)
⇒
⇒
⇒
⇒
⇒
![(38)/(4) =x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hpe4ra8zrqfnfr1ntv5il0vwpp6aj4pclo.png)
⇒
Thus the cost of 1 adult ticket is $9.5